(Q) A man sold two watches for Rs 525 each. On one he gains 10% and on the other he loses 15%. His profit or loss in the whole transaction is.
Solution:
= ((100×-5)-2×10×15)/110+85
= (-500-300)/195
= -4.10% ie Loss= 4.10% Ans.
By Concept:
100x ×(100+10)/100 = 525
⇒ (100x×110)/100 = 525
∴ x= 525/110
C.P of 1st watch= 100x
= 100×525/110
= Rs 477.27
Now,
100x × (100-15)/100 = 525
⇒ (100x×85)/100 = 525
∴ x= 525/85 = 6.17
C.P of 2nd watch=100x
= 100×6.17
= Rs 617
Now,
Total C.P= Rs(477.27+617)
= Rs 1094.27=1094
Total S.P= 525+525 = Rs 1050
Loss= C.P – S.P
= Rs(1094 – 1050)
= Rs 48
% Loss= (48×100)1094
= 4.10% Ans.
(Q)A vendor bought bananas at 6 for Rs 10 and sold them at 4 for Rs 6.Find his gain or loss percent.
Solution: By Concept And Shortcut Tricks
Step-2:
C.P= 40 and S.P= 36
Loss= C.P – S.P => 40 – 36 = Rs 4
% Loss= (4×100)/40
= 10% Ans.
CONCEPT:[इस Type के Problem को solve करते Time Object को Only Equal बनाना है| एवं Object को equal बनाने के लिए जिस Number से Multiply किया जायेगा उसी Number से Rate वाले part को Multiply करना है]
Note: Above वाले method से आप लोग इस तरह के problem को 10 sec में solve कर सकते है और Formula याद रखने के कोई जरूरत नहीं है|
(Q)A man buys lemons at the rate of 3 for Rs 5 and sells them at 2 for Rs 4 what is the profit percent?
Solution: By Concept And Shortcut Tricks
C.P=Rs 10 and S.P=Rs 12
Profit= S.P – C.P
=Rs(12-10) = Rs 2
% profit= (2×100)/10
= 20% Ans.
(Q)A man purchases some oranges at a rate of 3 for Rs 40 and same quantity at 5 for Rs 60. If he sells all the oranges at the rate of 3 for Rs 50, find his gain or loss percentage.
Solution: By Concept And Shortcut Tricks
Now,
C.P=Rs 380 And S.P=Rs 500
Profit= S.P – C.P
= Rs(500 – 380)
= Rs 120
% profit= (120×100)/380
= 32% Ans.
The common and frequently asked a question of Profit and Loss Problem with solution and Shortcut Tricks for Bank PO, SSC CGL, SSC CHSL, Railway Exam Type-3.1
(Q)The cost price of 15 articles is same as the selling price of 10 articles. The profit percent is.
Solution: By Concept And Shortcut Tricks
C.P of 15 articles = S.P of 10 articles
C.P/S.P = 10/15
Profit= S.P – C.P
=> 15-10 => 5 articles
∴ Profit %= (5×100)/10
= 50% Ans.
By Tricks:
= ((15-10)/10)×100
= (5/10)×100
= 50% Ans.
(Q)The selling price of 12 objects is equal to the cost price of 9 objects. Find the Loss or Profit percentage?
Solution: By Concept And Shortcut Tricks
S.P of 12 objects = C.P of 9 objects
S.P/C.P = 9/12
Note:C.P>S.P so loss
Loss= C.P – S.P
= 12 – 9 = 3
%Loss= (3×100)/12
= 25% Ans.
By Tricks:
= ((12-9)/12)×100
= (3/12)×100
= 25% Ans.
(Q)By selling 33m cloth a shopkeeper earns profit equivalent to selling price of 11m. Find his profit percent.
Solution: By Concept And Shortcut Tricks
Profit = S.P – C.P
S.P(11m) = s.p(33m) – C.P(33m)
⇒ C.P(33m) = s.p(33m) – S.P(11m)
⇒ C.P(33m) = s.p(22m)
⇒C.P/S.P = 22m/33m
Profit= 33m – 22m = 11m
% Profit= (11×100)/22
= 50% Ans
By Tricks:
% Profit= (Profit/S.P-Profit)×100
= (11/33-11)×100
= (11/22)×100
= 50% Ans.
(Q)By selling 33m, a shopkeeper incurs loss equivalent to the cost price of 11m. Find his loss percent.
Solution: By Concept And Shortcut Tricks
Loss = C.P – S.P
C.P(11m) = C.P(33m) – S.P(33m)
⇒ S.P(33m) = C.P(33m) – C.P(11m)
⇒ S.P(33m) = C.P(22m)
⇒ S.P/C.P = 22m/33m
Loss= (33-22)m = 11m
%Loss= (11×100)/33
= 33 ¹/3% Ans.
The common and frequently asked a question of Profit and Loss Problem with solution and Shortcut Tricks for Bank PO, SSC CGL, SSC CHSL, Railway Exam Type-3.2
If two article are sold at equal prices, the First one is sold at X% profit whereas the second one at a loss of X% then the seller always incurs a loss in the entire Transition.
It is equal to ( X)²/100
(Q) A dealer sold two T.V sets for Rs 7400 each on one he gained 10% and on the other, he lost 10%. The dealer’s loss or gain in the transaction is.
Solution:
% Loss = ( X)²/100
= (10)²/100
= 100/100 = 1% Ans.
(Q) a dealer sold two T.V sets for Rs 990 each on one he gained 10% and on the other he lost 10%. Then
(1)Find total C.P of T.V.
(2)His loss on the whole in Rs is.
Solution:
% Loss= ( X)²/100
= (10)²/100
= 100/100 = 1%
x × (100-1)/100 = 1980
x × 99/100 = 1980
∴ x = (1980×100)/99
= Rs 2000 Ans.
(2)Loss= C.P – S.P
= Rs(2000 – 1980)
= Rs 20 Ans.
The common and frequently asked a question of Profit and Loss Problem with solution and Shortcut Tricks for Bank PO, SSC CGL, SSC CHSL, Railway Exam Type-3.3
Trick: If two article is bought at equal prices, the First one is sold at X% profit whereas the second one at a loss of X% then the seller always incurs a no loss and no profit in the entire Transition.
(Q)A dealer bought two T.V sets for Rs 7400 each. The First one is sold at 10% profit whereas the second one at a loss of 10%. Then find out loss or gain in the transaction.
Solution: No Loss And No Profit.
Note:[We know that If two article is bought at an equal price, the First one is sold at X% profit whereas the second one at a loss of X% then the seller always incurs a no loss and no profit in the entire Transition.]
The common and frequently asked a question of Profit and Loss Problem with solution and Shortcut Tricks for Bank PO, SSC CGL, SSC CHSL, Railway Exam Type-3.4
Trick: If two article are sold at equal prices, the First one is sold at P% profit whereas the second one at a loss of L% then the
Note: If +ve then profit or if -ve then loss