(Q)A sold an article to B at the profit of 25%.B sold it to C loss of 10% and C sold it to D at the profit of 20%.If D paid Rs 27 then how much A paid to buy the article.
Solution:
Let C.P of A=100x
100x ×(125/100)×(90/100)×(120/100)= Rs 27
∴ x=(27×100×100×100)/(100×125×90×120)
=0.2
C.P of A = 100x => 100×0.2
=Rs 20 Ans.
(Q)A sold a horse to B for Rs 4800 by losing 20%.B sells it to C at a price which would have given A a profit of 15% B’s gain is.
Solution:
Let C.P of A=100x
100x × (80/100) = 4800
80x = 4800
∴ x = 60
C.P of A=100x => 100 × 60
=Rs 6000
Now,
6000 × (115/100) = S.P of A
S.P of A(i.e C.P Of C) = 6900
Gain of B = 6900 – 4800
= Rs 2100 Ans.
(Q)By selling an article for Rs 600 a man gains 20%. At what price should he have sold it to gain 15%?
Solution:
Step-1
100x × (100+20)/100 = Rs 600
120x = Rs 600
x = 5
∴ C.P= 100x
= 100 × 5
= Rs 500
Step-2
500 × (100+15)/100 = S.P
S.P= Rs 575 Ans.
BY TRICK:
Desire Gain(D Gain)= 15%
Normal Gain= 20%
S.P= Rs(600×(100+D Gain))/(100+Gain)
= Rs(600 × 115)/120
= Rs. 575 Ans.
(Q)By selling an article for Rs 720 a man loss 20%. At what price should he have sold it to loss 15%?
Solution:
Step-1
100x × (100-20)/100 = 720
80x = 720
∴ x = 720/80 = 9
C.P= 100x => 100×9=Rs 900
Step-2
900 × (100-15)/100 = S.P
900 × (85/100) = S.P
S.P= Rs 765 Ans.
BY TRICK:
Desire Loss(D Loss)=15%
Loss = 20%
S.P= Rs(720 × (100-D Loss))/(100-Loss)
= Rs(720 × 85)/80
= Rs 765 Ans.
(Q)By selling 80 ball pens for Rs 140 a retailer loses 30%. How many ball pens should he sell for Rs 104 so as to make a profit of 30%?
Solution:
Step-1:
100x × (100-30)/100 = 140
70x = 140
x= 2
∴ C.P= 100x => 100×2 = Rs 200
Step-2:
200 × (100+30)/100=S.P
S.P= Rs 260
Now,
Rs 260=80 ball pen
∴ Rs 104=(80/260)×104
=32 ball pens Ans
BY TRICK:
Desire Profit(D-Profit)=30%
Loss= 30%
S.P= Rs(140×(100+D Gain))/(100-loss)
= Rs(140 × 130)/70
= Rs. 260
Now,
Rs 260 = 80 ball pen
∴ Rs 104= (80/260)×104
= 32 ball pens Ans
(Q)A man sells a car to his friend at 10% loss. If the friend sells it for Rs 54,000 and gains 20% the original cost price of the car was.
Solution:
Let Original Cost Price or C.P of a Man=100x
100x × ((100-10)/100)×(100+20)/100 = 54000
=>100x × (90/100)×120/100 = 54000
⇒108x = 54000
∴ x = 500
Original C.P= 100x => 100×500
=Rs 50000 Ans.
(Q)If a man were to sell his chair for Rs. 720, he would loss 25%.To gain 25% he would sell it for.
Solution:
Step-1
100x × (100-25)/100 = 720
75x = 720
∴ x = 720/75
C.P = 100x
= 100 × (720/75)
= Rs. 960
Step-2
960 × (100+25)/100 = S.P
960 × (125/100) = S.P
S.P = Rs. 1200 Ans.
BY TRICK:
Desire Gain(D Gain)= 25%
Loss= 25%
S.P= Rs(720×(100+D Gain))/(100-loss)
= Rs(720 × 125)/75
= Rs. 1200 Ans.
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