Step-2:

C.P= 40 and S.P= 36

Loss= C.P – S.P => 40 – 36 = Rs 4

% Loss= (4×100)/40

= 10% Ans.

CONCEPT:[इस Type के Problem को solve करते Time Object को Only Equal बनाना है| एवं Object को equal बनाने के लिए जिस Number से Multiply किया जायेगा उसी Number से Rate वाले part को Multiply करना है]

Note: Above वाले method से आप लोग इस तरह के problem को 10 sec में solve कर सकते है और Formula याद रखने के कोई जरूरत नहीं है|

(Q)A man buys lemons at the rate of 3 for Rs 5 and sells them at 2 for Rs 4 what is the profit percent?

Solution: By Concept And Shortcut Tricks

C.P=Rs 10 and S.P=Rs 12

Profit= S.P – C.P

=Rs(12-10) = Rs 2

% profit= (2×100)/10

= 20% Ans.

(Q)A man purchases some oranges at a rate of 3 for Rs 40 and same quantity at 5 for Rs 60. If he sells all the oranges at the rate of 3 for Rs 50, find his gain or loss percentage.

Solution: By Concept And Shortcut Tricks

Now,

C.P=Rs 380 And S.P=Rs 500

Profit= S.P – C.P

= Rs(500 – 380)

= Rs 120

% profit= (120×100)/380

= 32% Ans.

The common and frequently asked a question of Profit and Loss Problem with solution and Shortcut Tricks for Bank PO, SSC CGL, SSC CHSL, Railway Exam Type-3.1

(Q)The cost price of 15 articles is same as the selling price of 10 articles. The profit percent is.

Solution: By Concept And Shortcut Tricks

C.P of 15 articles = S.P of 10 articles

C.P/S.P = 10/15

Profit= S.P – C.P

=> 15-10 => 5 articles

∴ Profit %= (5×100)/10

= 50% Ans.

By Tricks:

= ((15-10)/10)×100

= (5/10)×100

= 50% Ans.

(Q)The selling price of 12 objects is equal to the cost price of 9 objects. Find the Loss or Profit percentage?

Solution: By Concept And Shortcut Tricks

S.P of 12 objects = C.P of 9 objects

S.P/C.P = 9/12

Note:C.P>S.P so loss

Loss= C.P – S.P

= 12 – 9 = 3

%Loss= (3×100)/12

= 25% Ans.

By Tricks:

= ((12-9)/12)×100

= (3/12)×100

= 25% Ans.

(Q)By selling 33m cloth a shopkeeper earns profit equivalent to selling price of 11m. Find his profit percent.

Solution: By Concept And Shortcut Tricks

Profit     =    S.P – C.P

S.P(11m) = s.p(33m) – C.P(33m)

⇒ C.P(33m) = s.p(33m) – S.P(11m)

⇒ C.P(33m) = s.p(22m)

⇒C.P/S.P = 22m/33m

Profit= 33m – 22m = 11m

% Profit= (11×100)/22

= 50% Ans

By Tricks:

% Profit= (Profit/S.P-Profit)×100

= (11/33-11)×100

= (11/22)×100

= 50% Ans.

(Q)By selling 33m, a shopkeeper incurs loss equivalent to the cost price of 11m. Find his loss percent.

Solution: By Concept And Shortcut Tricks

Loss     = C.P – S.P

C.P(11m) = C.P(33m) – S.P(33m)

⇒ S.P(33m) = C.P(33m) – C.P(11m)

⇒ S.P(33m) = C.P(22m)

⇒ S.P/C.P = 22m/33m

Loss= (33-22)m = 11m

%Loss= (11×100)/33

= 33 ¹/3% Ans.

The common and frequently asked a question of Profit and Loss Problem with solution and Shortcut Tricks for Bank PO, SSC CGL, SSC CHSL, Railway Exam Type-3.2

If two article are sold at equal prices, the First one is sold at X% profit whereas the second one at a loss of X% then the seller always incurs a loss in the entire Transition.

It is equal to ( X)²/100

(Q) A dealer sold two T.V sets for Rs 7400 each on one he gained 10% and on the other, he lost 10%. The dealer’s loss or gain in the transaction is.

Solution:

% Loss = ( X)²/100

= (10)²/100

= 100/100 = 1% Ans.

(Q) a dealer sold two T.V sets for Rs 990 each on one he gained 10% and on the other he lost 10%. Then

(1)Find total C.P of T.V.

(2)His loss on the whole in Rs is.

Solution:

% Loss= ( X)²/100

= (10)²/100

= 100/100 = 1%

x × (100-1)/100 = 1980

x × 99/100 = 1980

∴ x = (1980×100)/99

= Rs 2000 Ans.

(2)Loss= C.P – S.P

= Rs(2000 – 1980)

= Rs 20 Ans.

The common and frequently asked a question of Profit and Loss Problem with solution and Shortcut Tricks for Bank PO, SSC CGL, SSC CHSL, Railway Exam Type-3.3

Trick: If two article is bought at equal prices, the First one is sold at X% profit whereas the second one at a loss of X% then the seller always incurs a no loss and no profit in the entire Transition.

(Q)A dealer bought two T.V sets for Rs 7400 each. The First one is sold at 10% profit whereas the second one at a loss of 10%. Then find out loss or gain in the transaction.

Solution: No Loss And No Profit.

Note:[We know that If two article is bought at an equal price, the First one is sold at X% profit whereas the second one at a loss of X% then the seller always incurs a no loss and no profit in the entire Transition.]

The common and frequently asked a question of Profit and Loss Problem with solution and Shortcut Tricks for Bank PO, SSC CGL, SSC CHSL, Railway Exam Type-3.4

Trick: If two article are sold at equal prices, the First one is sold at P% profit whereas the second one at a loss of L% then the

Note: If +ve then profit or if -ve then loss