For Example:

(Q1)Successive discounts of 30% and 20% are equivalent to a single discount of.

Solution:

=44% Ans.

(Q2)A single discount equivalent to the successive discounts of 10%, 20%, and 25% is.

Solution:

 =28%

Now,

=46% Ans.

(Q3)The difference between successive discounts of 40% followed by 30% and 45% followed by 20% on the marked price of an article is Rs 12. The marked price of the article is.

Solution:

 =58%

=56%

Let M.P=100x

Difference=58%-56%=2%

According to the question

100x×(2/100)=12

 so, x=6

∴ M.P=100x=100×6

=Rs 600 Ans.

(Q4)The marked price of an article is Rs 500. It is sold at successive discounts of 20% and 10%. The selling price of the article is.

Solution:

=28%

Now,

500×(100-28)/100=S.P

⇒  500×(72/100)=S.P

∴  S.P=Rs 360 Ans.

(Q5)A trader allows two successive discounts of 30% and 15% on selling an article. If he gets Rs 476 for that article, Find its marked price.

Solution:

   =40.5%

Now,

100x×(100-40.5)/100=476

⇒ 100x×(59.5/100)=476

x=476/59.5

∴ M.P=100x=100×(476/59.5)

=Rs 800 Ans.

(Q6)The difference between a discount of 30% on Rs 2000 and two successive discounts of 25% and 5% on the same amount is.

Solution:

Discount=2000×(30/100)

                  = Rs 600

 =28.75%

Now,

Discount=2000×(28.75/100)

                  = Rs 575

∴ Difference=Rs(600-575)

                        = Rs 25 Ans.

(Q7)A dealer buys a car listed at 200000 at successive discounts of 10% and 5%. If he sells the car for 179550, then his profit percent is.

Solution:

 =14.5%

[Concept: suppose dealer company से कार खरीदता है| company car का marked price 2००००० रखता है or company car पर two successive discounts दे रहा है 10% and 5%. इससे company का selling price निकाल लेंगे, company का जो selling price होगा वह dealer का cost price होगा|]

200000×(100-14.5)/100=S.P

200000×(85.5/100)=S.P

S.P=Rs 171000

C.P of dealer=Rs 171000

S.P of dealer(Given)=Rs 179550

Gain=Rs(179550-171000)

         =Rs 8550

% profit=(8550×100)/171000

               =5% Ans

(Q8)A dealer buys a table listed at Rs 1500 and gets successive discounts of 20% and 10%. He spends Rs 20 on transportation and sells it at a profit of 20%. Find the selling price of the table.

Solution:

=28%

[Concept: suppose dealer company से Table खरीदता है| company Table का marked price 1500 रखता है or company Table पर two successive discounts दे रहा है 20% and 10%. इससे company का selling price निकाल लेंगे, company का जो selling price होगा वह dealer का cost price होगा|]

1500×(100-28)/100=S.P

1500×(72/100)=S.P

S.P=Rs 1080

C.P of dealer=Rs 1080

Total C.P of dealer=Rs(1080+20)

    =Rs 1100

1100×(100+20)/100=S.P

1100×(120)/100=S.P

S.P=Rs 1320 Ans.

(Q9)The marked price of a watch is 1600. The shopkeeper gives successive discounts of 10% and x% to the customer. If the customer pays Rs 1224 for the watch. The value of x.

Solution:

1600×(100-10)/100=S.P

⇒1600×(90/100)=S.P

S.P=Rs 1440

Now,

(S.P after x% discount)

[Concept:C.P of customer=1224 i.e S.P of shopkeeper]

1440×(100-x)/100=1224

144000-1440x=122400

x=15% Ans.

(Q10)A bicycle marked at Rs 2000 is sold with two successive discount of 20% and 10%. An additional discount of 5% is offered for cash payment. The selling price of the bicycle at cash payment is.

Solution:

       =28%

Now,

=31.6%

=2000×(100-31.6)/100=S.P

=2000×(68.4/100)=S.P

∴ S.P=Rs 1368 Ans.