(Q)A contractor was engaged to construct a road in 16 days. After working for 12 days with 20 labours it was found that only 5/8th of the road had been constructed.To complete the work in stipulated time the number of extra labours required is.
Solution:
Let total work=1
20 workers will do 5/8 work in 12 days
Remaining work=1-(5/8)=3/8
Remaining time=16-12=4 days
Let number of extra labours=x
Now,
⇒ 20×12×3 = (20+x)×4×5
∴ x= 16 labours Ans.
(Q)Mohan completes 2/3 of his work in 10 days. Time he will take to complete 3/5 of the same work is.
Solution:
The common and frequently asked a question of Time And Work Problem with solution and Shortcut Tricks for Bank PO, SSC CGL, SSC CHSL, Railway Exam Type-4.4.
(Q)15 men take 20 days to complete a job working 8 hours a day. The number of hours a day should 20 men take to complete the job in 12 days.
Solution:
(Q)If 90 men can do a certain job in 16 days, working 12 hours per day, then the part of that work which can be completed by 70 men in 24 days, working 8 hours per day is.
Solution:
(Q)8 workers can build a wall 18m long, 2m broad and 12m high in 10 days, working 9 hours a day. Find how many workers will be able to build a wall 32m long, 3m broad and 9m high in 8 days working 6 hours a day.
Solution:
(Q)2 men and 3 boys can complete a work in 10 days, while 3 men and 2 boys can complete in 8 days. In how many days can 2 men and 1 boy complete the same work?
Solution:
Let 1 man=m unit work per day
1 women=w unit work per day
Now,
Note:[ 1 man=7 unit work per day 1 boy=2 unit work per day]
[Concept:eqn-1 or eqn-2 में m and b का value रखने पर जो value प्राप्त होगा वह total work होगा |]
Put the value of m and b in eqn-1
=(2×7+3×2)×10
=200 unit i.e total work
Now,
work done by 2 men and 1 boy in 1 day
=2m+1b=(2×7+1×2)
=16 unit
so, total time taken by 2 men and 1 boy=200/16
=12 ½ days Ans.
(Q)10 man and 15 women together can complete a piece of work in 6 days. A man alone can complete the work in 100 days. In how many days can one woman alone complete the work?
Solution:
Let 1 man=m unit work per day
1 women=w unit work per day
Note:[1 man=9 unit work per day1 woman=4 unit work per day]
[Concept:eqn-1 or eqn-2 में m and w का value रखने पर जो value प्राप्त होगा वह total work होगा |]
Put the value of m in eqn-2
=100×9
=900 unit i.e total work
Now,
1 woman=4 unit work per day
so, the total time taken by 1 woman=900/4
=225 days Ans.
The common and frequently asked a question of Time And Work Problem with solution and Shortcut Tricks for Bank PO, SSC CGL, SSC CHSL, Railway Exam Type-4.1.
(Q)If 8 men or 12 boys can do a piece of work in 16 days, the number of days required to complete the work by 20 men and 6 boys is.
Solution:
Let 1 man=m unit work per day
1 boy=b unit work per day
Now,
Note:[ 1 man=3 unit work per day 1 boy=2 unit work per day]
[Concept:eqn-1 or eqn-2 में m and b का value रखने पर जो value प्राप्त होगा वह total work होगा |]
Put the value of m in eqn-1
=(8×3)×16
=384 i.e total work
Now,
work done by 20 men and 6 boy in 1 day
=20m+6b=(20×3+6×2)
=72 unit
so, the total time taken by 20 men and 6 boy=384/72
=5 ¹/3 days Ans.
(Q)If 4 men or 6 women can do a piece of work in 12 days working 7 hours a day; how many days will it take to complete a work twice as large with 10 men and 3 women working together 8 hours a day?
Solution:
Let 1 man=m unit work per day
1 boy=b unit work per day
Now,
Note:[ 1 man=3 unit work per day 1 women=2 unit work per day]
[Concept:eqn-1 or eqn-2 में m and w का value रखने पर जो value प्राप्त होगा वह total work होगा |]
Put the value of m in eqn-1
=(4×3)×84
=1008 unit i.e total work
Now,
work done by 10 men and 3 women in 1 day
=10m+3w=(10×3+3×2)
=36 unit
so, the total time taken by 10 men and 3women=(2×1008)/(36×8)
=7 days Ans.
(Q)If 1 men or 2 women or 3 boys can do a piece of work in 44 days, then the same piece of work will be done by 1 man, 1 woman and 1 boy in.
Solution:
Let 1 men=m unit work per day
1 woman=w unit work per day
1 boy=b unit work per day
put the value of m in eqn-1
=(1×6)×44
=264 unit i.e total work
work done by 1 man, 1 women and 1 boy in 1 day
=1m+1w+1b=(1×6+1×3+1×2)
=11 unit
so, the total time taken by 1 man, 1 women and 1 boy=264/11
=24 days Ans.
The common and frequently asked a question of Time And Work Problem with solution and Shortcut Tricks for Bank PO, SSC CGL, SSC CHSL, Railway Exam Type-4.2.
(Q)Some staff promised to do a job in 18 days, but 6 of them went on leave. So the remaining men took 20 days to complete the job. How many men were there originally?
Solution:
Let number of men originally=x
∴ M1D1 = M2D2
⇒x×18 = (x-6)×20
⇒-2x = -144
∴ x=60 men Ans.
(Q)A certain number of men can do a piece of work in 40 days. If there were 45 men more the work could have been finished in 25 days. Find the original number of men employed in the work.
Solution:
Let number of men originally=x
∴ M1D1 = M2D2
⇒x×40 = (x+45)×25
⇒15x =1125
∴ x=75 men Ans.
(Q)A certain number of men can do a work in 40 days. If there were 8 men more, it could be finished in 10 days less. How many men were there initially?
Solution:
Let number of men originally=x
∴ M1D1 = M2D2
⇒x×40 = (x+8)×30
⇒10x =240
∴ x=24 men Ans.
The common and frequently asked a question of Time And Work Problem with solution and Shortcut Tricks for Bank PO, SSC CGL, SSC CHSL, Railway Exam Type-4.3.
(Q)A company employed 200 workers to complete a certain work in 150 days. If only one-fourth of the work has been done in 50 days, then in order to complete the whole work in time, the number of additional workers to be employed was.
Solution:
Let total work=1
200 workers will do 1/4 work in 50 days
Remaining work=1-(1/4)=3/4
Remaining time=150-50=100 days
Let number of additional workers=x
Now,
x=100 Ans.
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