Trick-1: If A can do a certain work in x days and B can complete same work in y days if they work together then they will complete the work in
For Example:
(Q1)A can do a certain work in 10 days and B can complete same work in 15 days if they work together then in how many days works gets done.
Solution:
(A+B)’s 1 day work=3+2=5 unit
Time taken by (A+B)=30/5
= 6 days Ans.
Rough:[L.C.M of 10 and 15=30 now 30/10=3 unit and 30/15=2 unit]
BY TRICK:
Trick-2: If A, B, and C can do a certain work in x days, y days, and z days respectively. if they work together then they will complete the work in
For Example:
(Q1) Ram, Mohan, and Sita can do a work in 6, 12 and 24 days respectively. In what time will they finish the work while working together?
Solution:
(Ram+Mohan+Sita) 1 day work=4+2+1
=7 unit
Required Time=24/7=3 ³/7 Ans.
BY TRICK:
Trick-3: A and B together can do a work in x days, B and C together in y days, while C and A together in z days. If they all work together, the work will be completed in.
For Example:
(Q1)A and B together can do a work in 8 days, B and C together in 6 days, while C and A together in 10 days. If they all work together, the work will be completed in.
Solution:
(A+B)+(B+C)+(C+A) 1 day work=15+20+12=47 units
i.e 2(A+B+C)1 day work=47 units
∴ (A+B+C)1 day work=47/2 units
Time Taken by(A+B+C)=120/(47/2)
BY TRICK:
Common Type Of Time and Work Problem Shortcut Tricks That Are Frequently Asked In Various Competitive Exam
Trick-4: A and B together can do a piece of work in x days. If A alone can do it in y days, in how many days B can alone complete the same piece of work
For Example:
(Q1)A and B together can do a piece of work in 4 days. If A alone can do it in 6 days, in how many days B can alone complete the same piece of work?
Solution:
Time taken by B=12/1
= 12 Days Ans.
By Trick:
(Q2)A man can do a piece of work in 5 days, but with the help of his son he can do it in 3 days. In what time can the son do it alone?
Solution:
Time taken by son alone=15/2
=7.5 Days Ans.
By Trick:
(Q3)A can do a piece of work in 16 days and B can do the same piece of work in 12 days. With the help of C, they did in 4 days only. Then, C alone can do the job in?
Solution:
Time taken by C=48/5 days Ans.
Common Type Of Time and Work Problem Shortcut Tricks That Are Frequently Asked In Various Competitive Exam
Trick-5: If A and B together can complete a piece of work in x days; B and C together in y days; and C and A together in z days. How many days will each take separately to complete the same work?
(Q1)A and B together can complete a piece of work in 24 days; B and C together in 30 days; and C and A together in 40 days. How many days will each take separately to complete the same work?
Solution:
(A+B)+(B+C)+(C+A) 1 day work=5+4+3=12 units
i.e 2(A+B+C)1 day work=12 units
∴ (A+B+C)1 day work=12/2 units
=6 units.
Efficiency of A=(A+B+C)-(B+C)
=6 Units – 4 Units
=2 Units
Efficiency of B=(A+B+C)-(C+A)
=6 Units – 3 Units
=3 Units
Efficiency of C=(A+B+C)-(A+B)
=6 Units – 5 Units
=1 Units
Time taken by A=120/2
=60 Days
Time taken by B=120/3
=40 Days
Time taken by A=120/1
=120 Days
BY TRICK:
(Q2)A and B can do a given piece of work in 8 days, B and C can do the same work in 12 days and A, B, C complete it in 6 days. Number of days required to finish the work by A and C is.
Solution:
Efficiency of A=(A+B+C)-(B+C)
=4 Units – 2 Units
=2 Units
Efficiency of C=(A+B+C)-(A+B)
=4 Units – 3 Units
=1 Units
(A+C)’s 1 day work=2+1=3 unit
Time taken by( A+C)=24/3
=8 days Ans.