IMPORTANT PERCENTAGE PROBLEM CONCEPTS SHORTCUT TRICKS FOR COMPETITIVE EXAM

(Q1)If Ravi salary is 25 % more than Raju’s salary the percentage by which Raju’s salary is less then Ravi salary.

Solution: BY TRICK

Required percentage=(25/100+25)×100)

(Q2)If A’s income is 50% less than that of B’s, then B’s income is what percent more than that of A?

Solution: BY TRICK

Required percentage:(50/100−50)×100

=(50/50)×100

=100% Ans

(Q3)Two numbers are more than the third number by 20% and 50% respectively. The first number is what percent of the second number?

Solution: Let third number=100

First number=120

Second number=150

∴ Required percentage=(120/150)×100

=80% Ans.

BY TRICK:

 ∴ Required percentage=(100+20/100+50)×100

                                                 =80% Ans.

(Q4)Two numbers are less than a third number by 30% and 37% respectively.The percent by which the second number is less than the first is.

Solution: Let the third number=100

First number=70

Second number=63

∴ Required percentage=(7/70)×100

=10% Ans.

(Q5)Two numbers are respectively 20% and 50% more than a third number. the ratio of the two numbers is.

Solution: Let the third number=100

First number=120

Second number=150

∴ Required ratio=120/150

=4/5

=4:5 Ans.

(Q6)25% of the annual salary of A is equal to 80% of the annual salary of the B.Monthly salary of B is 40% of the monthly salary of the C.Annual salary of C is Rs. 6 lac. what is the monthly salary of A?

Solution: monthly salary of C=600000/12

=Rs 50000

B’s monthly salary=(50000×40)/100

=Rs 20000

Annual salary of B=20000×12

=240000

Now,

Let Annual salary of A=X

( X×25)/100=(240000×80)/100

=>25X = 240000×80

∴ X=(240000×80)/25

=Rs 768000

monthly salary of A=768000/12

=Rs 64000 Ans.

(Q7)The monthly salaries of A and B together amount to Rs 40,000.A spends 85% of his salary and B, 95% of his salary.if now their saving is the same, then the salary(in Rs) of A is.

Solution: Let salary of A=X

salary of B=40000−X

Saving of A=15%

Saving of B=5%

Now according to question their saving are same so

( X×15)/100=(40000−X)×5/100

=>15X=200000−5X

=>20X=200000

∴ X=Rs 10000 Ans.

(Q8)Mohan donated 3% of his income to a charity and deposited 12% of the rest in the bank.if now he has Rs.12804, then his income was.

Solution:

               Let income=100x

 Now,

  85.36x=12804

  ∴ x=150

  income=100x

 =100×150

 =Rs 15000 Ans.

     Rough:

      (100x×3)/100=3x

      rest=100x-3x=97x

     deposit=12% of rest i.e 97x

     (97x×12)/100

     =11.64x

     remaining=97x−11.64x=85.36x

(Q9)Mohan saves 14% of his salary while Shyam saves 22%. if both get the same salary and Shyam saves Rs. 1540, what is the saving of Mohan?

Solution: According to question Shyam saves 22% i.e equal to 1540

   now,

   22%=1540

   ∴ 1%=1540/22

  ∴100%=(1540/22)×100

  =Rs 7000 salaries of Shyam

  saving of ram=(7000×14)/100

 =Rs.980 Ans.